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Maths and IQ problems

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ElansarGelmir Male
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  #31 Old 15-04-2005 Default

Quote:
Originally Posted by prince
Actually it can be followed by anything since I can create a pattern from any finite sequence.

But I think you're seeking for
211213
There might be another possible way
122113
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ElansarGelmir Male
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  #32 Old 15-04-2005 Default

Quote:
Originally Posted by topdog
U, D, T, Q, C, S, S, O...
N?

Here's another one [URGH!!! Got to go back to my Chem]

A man wanted to marry a woman. She agreed to marry him, if and only if he can guess the age of all her 3 daughters. She gave him 2 clues:
1. The product of the age of her daughters is [edited: 36]
2. The sum of the age of her daughters equals to the address of the house next door

The man made some calculations, went out to find out the address of the house next door, but still could not arrive with the answer. He begged for one more clue. Pitying the man (I think she wanted to marry him too), she gave him one more clue:
3. Her oldest daughter loves strawberry

Instantly, the guy got the answer and they were happily married to each other. The question: How did he solve it?
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littlebigone Male
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  #33 Old 15-04-2005 Default

i think the questions wrong.

He should be able to make the guess based on the first two clues.

There are only 5 unique combinations that i can find:
1,1,32
1,2,16
1,4,8
2,2,8
2,4,4

And they all give unique sums.

I think your first clue is wrong.

I think the puzzle is supposed to end up with som combination adding up to the same number which means he wouldn't be able to choose between the combinations. But then because she has an "oldest daughter", one of the combinations would have to have her having older twins. So by elimination, he guessed the correct ages.
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littlebigone Male
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  #34 Old 15-04-2005 Default

should be 36
then you'll get two combinations which add up to 13
1,6,6 and 2,2,9
so using the same logic, we see that the daughters's ages are 2,2,9
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someone
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  #35 Old 15-04-2005 Default

Yes. The question is wrong. the product of the 3 numbers should be 36. so that the factorizations can be
36, 1, 1 - 38
18,2,1 - 21
9,4,1 - 14
9,2,2 - 13
6,6,1 - 13
6,3,2 - 11
4,3,3 -10
All the 3 numbers sum up to distinct numbers except the 13. so the address of the next door must be 13. he is not able to guess until he knows there's an 'oldest' daughter. therefore, between 9,2,2 and 6,6,1, he chose 9,2,2.
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  #36 Old 15-04-2005 Default

sorry.. i am late 8O
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ElansarGelmir Male
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  #37 Old 15-04-2005 Default

Oops...

Yeap... sorry... was posting this question while i was attempting my chem lab report... pai seh
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chiunlin
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  #38 Old 16-04-2005 Default

Here's another question:
A monk climbs up a hill following a path at starting from the bottom at 12pm. The next day, he climbs down the hill following the same path at 12pm. Prove that when the monk is going down the hill, the monk will reach a spot somewhere between the peak and the bottom where he was at at the same time at the day before.
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SpRInG
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  #39 Old 16-04-2005 Default

chiunlin, dun understand ur question lar
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bp_ffei
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  #40 Old 16-04-2005 Default

I think you should add assumptions, like he is travelling with constant speed etc.

Anyway, is it a maths question? I don't seem to see any trickery in the question...
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