Super Junior Member

#61
13042009
Re: Stpm 2009
i'm so sorry that i didn't realise i typed 2 instead of 1....
is the question 1 i don know how.... and to my knowledge, if not mistaken the question 2, that essay writing, all r writing bout facts rite??? correct me if i'm wrong.. how to interpret the graph and the table? i have read questions that contain few graphs and table in one question... how to start? how to write? 
Slightly Senior Member

#62
14042009
Re: Stpm 2009
Yes for essay part 1 we have to INTERGRATE the stimuli given besides identifying major trends.
Sometimes it's really tough as we can't see the link between the stimuli, and so we can't intergrate much... the essay in 2nd part is always the argumentative type. Last edited by sugarspice; 14042009 at 05:40 AM. 
Member

#63
15042009
Re: Stpm 2009
Anyway, if you guys free, try out this question. Maths question. I ought to be able to do it, but somehow got stuck.. actually, just helping my friend out only.. lolz.
log(base2)y = 3 + log(base2)x + log(base2)(x+1) It says to write X in terms of Y... I got until here. y/ [x(x+1)] = 8 Guess there must be another special method to do it.. 
Member

#64
15042009
Re: Stpm 2009
Very interesting question lol. I'm no maths expert, but may I suggest
x = (8 + (64+32y)^1/2)/16 Last edited by tsar; 15042009 at 01:00 PM. 
Member

#65
15042009
Re: Stpm 2009

Less Junior Member

#66
15042009
Re: Stpm 2009
use (b+(sqrt(b^24ac)))/2a after got y/ [x(x+1)] = 8

Member

#67
15042009
Re: Stpm 2009

Member

#68
15042009
Re: Stpm 2009
Lol his method is my method.
I thought the requirement of the question was to put x in terms of y? If you want to go for a solution you'll need 2 equations for 2 unknowns. 
Less Junior Member

#69
15042009
Re: Stpm 2009
Quote:
if you don't want use tat formula, you can use completing the square which will give you same thing. y/ [x(x+1)] = 8 y=8[x(x+1)] y=8((x+1/2)^21/4) . . i also just know that Last edited by uoykcuf; 15042009 at 03:29 PM. Reason: Automerged Doublepost 

Developer

#70
15042009
Re: Stpm 2009
log(base 2)y = 3 + log(base 2)x + log(Base 2)(x+1)
log(base 2)y = log(base 2)[(8x)(x+1)] y/8 = x(x+1) y/8 = x^2 + x y/8 = x^2 + x + 1/4  1/4 y/8 = (x+1/2)^2  1/4 (y/8 + 1/4)^1/2 = x + 1/2 [y>0 since it's a logarithm] therefore X = (y/8 + 1/4)^1/2  1/2 
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